change some sentences' format of the mkvm manpage
git-svn-id: https://svn.code.sf.net/p/xcat/code/xcat-core/trunk@9146 8638fb3e-16cb-4fca-ae20-7b5d299a9bcd
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		| @@ -60,13 +60,21 @@ B<-i>              Starting numeric id of the newly created partitions. For P7 I | ||||
| B<-m>              memory interleaving. The value only could be interleaved or non-interleaved. non-interleaved mode means the memory cannot be shared across the processors in an octant. interleaved means the memory can be shared. | ||||
|  | ||||
| B<-r>              partition rule. | ||||
|  | ||||
| If all the octants configuration value are same in one CEC,  it will be  " -r  0-7:value" . | ||||
|  | ||||
| If the octants use the different configuration value in one cec, it will be "-r 0:value1,1:value2,...7:value7", or "-r 0:value1,1-7:value2" and so on. | ||||
|  | ||||
| The octants configuration value for one Octant could be  1, 2, 3, 4, 5 . The meanings of the octants configuration value  are as following: | ||||
|  | ||||
| 1 - 1 partition with all cpus and memory of the octant | ||||
|  | ||||
| 2 - 2 partitions with a 50/50 split of cpus and memory | ||||
|  | ||||
| 3 - 3 partitions with a 25/25/50 split of cpus and memory | ||||
|  | ||||
| 4 - 4 partitions with a 25/25/25/25 split of cpus and memory | ||||
|  | ||||
| 5 - 2 partitions with a 25/75 split of cpus and memory | ||||
|  | ||||
| B<-l>              The partition name of the source. | ||||
| @@ -181,13 +189,21 @@ I<mkvm lpar1-lpar8 -i 1 -m non-interleaved  -r 0-7:1> | ||||
| Output is similar to: | ||||
|  | ||||
| lpar1: Success | ||||
|  | ||||
| lpar2: Success | ||||
|  | ||||
| lpar3: Success | ||||
|  | ||||
| lpar4: Success | ||||
|  | ||||
| lpar5: Success | ||||
|  | ||||
| lpar6: Success | ||||
|  | ||||
| lpar7: Success | ||||
|  | ||||
| lpar8: Success | ||||
|  | ||||
| cec1: Please reboot the CEC cec1 firstly, and then use chvm to assign the I/O slots to the LPARs | ||||
|  | ||||
| 7. For P7 IH, to create new partitions lpar1-lpar9, the lpar1 will use 25% CPU and 25% memory of the first octant, and lpar2 will use the left CPU and memory of the first octant. lpar3-lpar9 will use all the cpu and memory of each octant, enter: | ||||
| @@ -201,14 +217,23 @@ I<mkvm lpar1-lpar9 -i 1 -m non-interleaved  -r 0:5,1-7:1> | ||||
| Output is similar to:  | ||||
|  | ||||
| lpar1: Success | ||||
|  | ||||
| lpar2: Success | ||||
|  | ||||
| lpar3: Success | ||||
|  | ||||
| lpar4: Success | ||||
|  | ||||
| lpar5: Success | ||||
|  | ||||
| lpar6: Success | ||||
|  | ||||
| lpar7: Success | ||||
|  | ||||
| lpar8: Success | ||||
|  | ||||
| lpar9: Success | ||||
|  | ||||
| cec1: Please reboot the CEC cec1 firstly, and then use chvm to assign the I/O slots to the LPARs | ||||
|  | ||||
| =head1 FILES | ||||
|   | ||||
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