From bb9c8b23534be082c1776c97ea6e2b9eea5fcb08 Mon Sep 17 00:00:00 2001 From: jjhua Date: Fri, 25 Mar 2011 06:57:10 +0000 Subject: [PATCH] change some sentences' format of the mkvm manpage git-svn-id: https://svn.code.sf.net/p/xcat/code/xcat-core/trunk@9146 8638fb3e-16cb-4fca-ae20-7b5d299a9bcd --- xCAT-client/pods/man1/mkvm.1.pod | 25 +++++++++++++++++++++++++ 1 file changed, 25 insertions(+) diff --git a/xCAT-client/pods/man1/mkvm.1.pod b/xCAT-client/pods/man1/mkvm.1.pod index 767ab46da..8bd9f6293 100644 --- a/xCAT-client/pods/man1/mkvm.1.pod +++ b/xCAT-client/pods/man1/mkvm.1.pod @@ -60,13 +60,21 @@ B<-i> Starting numeric id of the newly created partitions. For P7 I B<-m> memory interleaving. The value only could be interleaved or non-interleaved. non-interleaved mode means the memory cannot be shared across the processors in an octant. interleaved means the memory can be shared. B<-r> partition rule. + If all the octants configuration value are same in one CEC, it will be " -r 0-7:value" . + If the octants use the different configuration value in one cec, it will be "-r 0:value1,1:value2,...7:value7", or "-r 0:value1,1-7:value2" and so on. + The octants configuration value for one Octant could be 1, 2, 3, 4, 5 . The meanings of the octants configuration value are as following: + 1 - 1 partition with all cpus and memory of the octant + 2 - 2 partitions with a 50/50 split of cpus and memory + 3 - 3 partitions with a 25/25/50 split of cpus and memory + 4 - 4 partitions with a 25/25/25/25 split of cpus and memory + 5 - 2 partitions with a 25/75 split of cpus and memory B<-l> The partition name of the source. @@ -181,13 +189,21 @@ I Output is similar to: lpar1: Success + lpar2: Success + lpar3: Success + lpar4: Success + lpar5: Success + lpar6: Success + lpar7: Success + lpar8: Success + cec1: Please reboot the CEC cec1 firstly, and then use chvm to assign the I/O slots to the LPARs 7. For P7 IH, to create new partitions lpar1-lpar9, the lpar1 will use 25% CPU and 25% memory of the first octant, and lpar2 will use the left CPU and memory of the first octant. lpar3-lpar9 will use all the cpu and memory of each octant, enter: @@ -201,14 +217,23 @@ I Output is similar to: lpar1: Success + lpar2: Success + lpar3: Success + lpar4: Success + lpar5: Success + lpar6: Success + lpar7: Success + lpar8: Success + lpar9: Success + cec1: Please reboot the CEC cec1 firstly, and then use chvm to assign the I/O slots to the LPARs =head1 FILES