161 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			161 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /*
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|  *  linux/arch/arm/common/icst525.c
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|  *
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|  *  Copyright (C) 2003 Deep Blue Solutions, Ltd, All Rights Reserved.
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|  *
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|  * This program is free software; you can redistribute it and/or modify
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|  * it under the terms of the GNU General Public License version 2 as
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|  * published by the Free Software Foundation.
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|  *
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|  *  Support functions for calculating clocks/divisors for the ICST525
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|  *  clock generators.  See http://www.icst.com/ for more information
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|  *  on these devices.
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|  */
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| #include <linux/module.h>
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| #include <linux/kernel.h>
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| 
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| #include <asm/hardware/icst525.h>
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| 
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| /*
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|  * Divisors for each OD setting.
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|  */
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| static unsigned char s2div[8] = { 10, 2, 8, 4, 5, 7, 9, 6 };
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| 
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| unsigned long icst525_khz(const struct icst525_params *p, struct icst525_vco vco)
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| {
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| 	return p->ref * 2 * (vco.v + 8) / ((vco.r + 2) * s2div[vco.s]);
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| }
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| 
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| EXPORT_SYMBOL(icst525_khz);
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| 
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| /*
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|  * Ascending divisor S values.
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|  */
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| static unsigned char idx2s[] = { 1, 3, 4, 7, 5, 2, 6, 0 };
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| 
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| struct icst525_vco
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| icst525_khz_to_vco(const struct icst525_params *p, unsigned long freq)
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| {
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| 	struct icst525_vco vco = { .s = 1, .v = p->vd_max, .r = p->rd_max };
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| 	unsigned long f;
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| 	unsigned int i = 0, rd, best = (unsigned int)-1;
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| 
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| 	/*
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| 	 * First, find the PLL output divisor such
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| 	 * that the PLL output is within spec.
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| 	 */
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| 	do {
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| 		f = freq * s2div[idx2s[i]];
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| 
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| 		/*
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| 		 * f must be between 10MHz and
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| 		 *  320MHz (5V) or 200MHz (3V)
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| 		 */
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| 		if (f > 10000 && f <= p->vco_max)
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| 			break;
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| 	} while (i < ARRAY_SIZE(idx2s));
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| 
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| 	if (i >= ARRAY_SIZE(idx2s))
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| 		return vco;
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| 
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| 	vco.s = idx2s[i];
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| 
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| 	/*
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| 	 * Now find the closest divisor combination
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| 	 * which gives a PLL output of 'f'.
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| 	 */
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| 	for (rd = p->rd_min; rd <= p->rd_max; rd++) {
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| 		unsigned long fref_div, f_pll;
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| 		unsigned int vd;
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| 		int f_diff;
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| 
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| 		fref_div = (2 * p->ref) / rd;
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| 
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| 		vd = (f + fref_div / 2) / fref_div;
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| 		if (vd < p->vd_min || vd > p->vd_max)
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| 			continue;
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| 
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| 		f_pll = fref_div * vd;
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| 		f_diff = f_pll - f;
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| 		if (f_diff < 0)
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| 			f_diff = -f_diff;
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| 
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| 		if ((unsigned)f_diff < best) {
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| 			vco.v = vd - 8;
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| 			vco.r = rd - 2;
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| 			if (f_diff == 0)
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| 				break;
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| 			best = f_diff;
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| 		}
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| 	}
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| 
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| 	return vco;
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| }
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| 
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| EXPORT_SYMBOL(icst525_khz_to_vco);
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| 
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| struct icst525_vco
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| icst525_ps_to_vco(const struct icst525_params *p, unsigned long period)
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| {
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| 	struct icst525_vco vco = { .s = 1, .v = p->vd_max, .r = p->rd_max };
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| 	unsigned long f, ps;
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| 	unsigned int i = 0, rd, best = (unsigned int)-1;
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| 
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| 	ps = 1000000000UL / p->vco_max;
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| 
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| 	/*
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| 	 * First, find the PLL output divisor such
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| 	 * that the PLL output is within spec.
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| 	 */
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| 	do {
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| 		f = period / s2div[idx2s[i]];
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| 
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| 		/*
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| 		 * f must be between 10MHz and
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| 		 *  320MHz (5V) or 200MHz (3V)
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| 		 */
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| 		if (f >= ps && f < 100000)
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| 			break;
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| 	} while (i < ARRAY_SIZE(idx2s));
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| 
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| 	if (i >= ARRAY_SIZE(idx2s))
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| 		return vco;
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| 
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| 	vco.s = idx2s[i];
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| 
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| 	ps = 500000000UL / p->ref;
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| 
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| 	/*
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| 	 * Now find the closest divisor combination
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| 	 * which gives a PLL output of 'f'.
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| 	 */
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| 	for (rd = p->rd_min; rd <= p->rd_max; rd++) {
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| 		unsigned long f_in_div, f_pll;
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| 		unsigned int vd;
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| 		int f_diff;
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| 
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| 		f_in_div = ps * rd;
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| 
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| 		vd = (f_in_div + f / 2) / f;
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| 		if (vd < p->vd_min || vd > p->vd_max)
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| 			continue;
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| 
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| 		f_pll = (f_in_div + vd / 2) / vd;
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| 		f_diff = f_pll - f;
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| 		if (f_diff < 0)
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| 			f_diff = -f_diff;
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| 
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| 		if ((unsigned)f_diff < best) {
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| 			vco.v = vd - 8;
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| 			vco.r = rd - 2;
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| 			if (f_diff == 0)
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| 				break;
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| 			best = f_diff;
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| 		}
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| 	}
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| 
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| 	return vco;
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| }
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| 
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| EXPORT_SYMBOL(icst525_ps_to_vco);
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