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Don't zero freed base memory; one block will contain librm.

This commit is contained in:
Michael Brown 2005-04-09 16:14:37 +00:00
parent 1f6dfd7047
commit e29e6456b0

View File

@ -22,17 +22,6 @@
#define fbms ( * ( ( uint16_t * ) phys_to_virt ( 0x413 ) ) )
#define FBMS_MAX ( 640 )
/* Structure that we use to represent a free block of base memory
*/
#define FREE_BLOCK_MAGIC ( ('!'<<0) + ('F'<<8) + ('R'<<16) + ('E'<<24) )
union free_base_memory_block {
struct {
uint32_t magic;
uint16_t size_kb;
};
char bytes[1024];
};
/* Local prototypes */
static void free_unused_base_memory ( void );
@ -188,12 +177,10 @@ static void free_unused_base_memory ( void ) {
free_block->size_kb, ( fbms << 6 ),
( fbms + free_block->size_kb ) << 6 );
/* Zero out freed block. We do this in case
* the block contained any structures that
* might be located by scanning through
* memory.
/* Do not zero out the freed block, because it might
* be the one containing librm, in which case we're
* going to have severe problems the next time we use
* DBG() or, failing that, call get_memsizes().
*/
memset ( free_block, 0, free_block->size_kb << 10 );
}
}