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Removed incorrect comment; malloc() is inefficient only when the
alignment and size are both powers of two, and there's no way to specify an alignment through the malloc() interface anyway.
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@ -195,11 +195,6 @@ void free_memblock ( void *ptr, size_t size ) {
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*
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* Allocates memory with no particular alignment requirement. @c ptr
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* will be aligned to at least a multiple of sizeof(void*).
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*
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* Note that malloc() is very inefficient for allocating blocks where
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* the size is a power of two; if you have many of these
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* (e.g. descriptor rings, data buffers) you should use malloc_dma()
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* instead.
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*/
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void * malloc ( size_t size ) {
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size_t total_size;
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