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Always send EOI. We can't feasibly share interrupts (since we have no

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clue what the "previous" interrupt handler will do, which could range
from "just an iret" to "disable the interrupt"), and that means that
we have to take responsibility for ACKing all interrupts.  Joy.
This commit is contained in:
Michael Brown 2007-01-13 14:45:26 +00:00
parent 86171c53f4
commit 6a3c76c8e0
1 changed files with 12 additions and 4 deletions
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16
src/arch/i386/drivers/net/undinet.c
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@ -390,19 +390,27 @@ static void undinet_poll ( struct net_device *netdev, unsigned int rx_quota ) {
/* Do nothing unless ISR has been triggered */
if ( ! undinet_isr_triggered() )
return;
/* See if this was our interrupt */
memset ( &undi_isr, 0, sizeof ( undi_isr ) );
undi_isr.FuncFlag = PXENV_UNDI_ISR_IN_START;
if ( ( rc = undinet_call ( undinic, PXENV_UNDI_ISR, &undi_isr,
sizeof ( undi_isr ) ) ) != 0 )
return;
/* Send EOI to the PIC. In an ideal world, we'd do
* this only for interrupts which the UNDI stack
* reports as "ours". However, since we don't (can't)
* chain to the previous interrupt handler, we have to
* acknowledge all interrupts. See undinet_hook_isr()
* for more background.
*/
send_eoi ( undinic->irq );
/* If this wasn't our interrupt, exit now */
if ( undi_isr.FuncFlag != PXENV_UNDI_ISR_OUT_OURS )
return;
/* Send EOI */
send_eoi ( undinic->irq );
/* Start ISR processing */
undinic->isr_processing = 1;
undi_isr.FuncFlag = PXENV_UNDI_ISR_IN_PROCESS;